Energy of a microwave in joules
WebTo heat 125 grams of water 80 degrees takes about 42,000 Joules, or 42 kJ. You can do this in about 35 seconds with 1200 watts (1200 Joules per second) or in about 70 seconds with 600 watts. It... WebApr 12, 2024 · With Joule's law of electric heating equation, we can determine the Joule equivalent of electrical energy. However, we know that energy is the product of power and time. Hence, the energy generated in Joules can be equated to a watt second. 1 watt-second = 1 Joule
Energy of a microwave in joules
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WebCalculate the energy of a photon of electromagnetic radiation at each of the following wavelengths: (in joules to 3 sig figs) 1) 12.24 cm (wavelength of a microwave oven) 2) 337.1 nm (microwave of a nitrogen laser) This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. WebMar 3, 2024 · W = 1.5 ⋅ 105J Explanation: Power is the rate at which work is done and can be expressed by the equation P = W t with units of Watts (W). We are given P = 500W and t = 5 min = 300s. We can use these values to calculate the work done. ⇒ W = P ⋅ t = (500W) ⋅ (300s) 150,000J ⇒ 1.5 ⋅ 105J
WebDec 15, 2016 · E = h ⋅ ν −−−−−−−− Here E is the energy of the photon h is Planck's constant, equal to 6.626 ⋅ 10−34J s ν is the frequency of the photon The problem provides you with the frequency of the photon, so just plug this value into the above equation and solve for E E = 6.626 ⋅ 10−34Js ⋅ 3.20 ⋅ 1011s−1 E = 2.12 ⋅ 10−22J −−−−−−−−−−−−−−−− WebThe power consumption of a microwave oven ranges between 1000 watts to 3000 watts. A typical oven of 21 Litres oven consumes 1200 watts of power. Calculate the energy …
WebJul 11, 2014 · The energy is 3.31 × 10−19J. EXAMPLE 2 Calculate the energy of a photon of radiation that has a wavelength of 3.3 µm. Solution 2 E = hc λ = 6.626 ×10−34J ⋅ s × 2.998 ×108m⋅s−1 3.3 × 10−6m = 6.0 × 10−20J Here's a video on how to find the energy of a photon with a given wavelength. Answer link WebOct 6, 2014 · With combined effect of microwave and joule heating the temperature value is about 1514C. This value of temperature is comparable with the reference furnace of …
WebWhat is the energy in joules of one proton of microwave radiation with a wavelength 0.122m? (c=2.9979x10^8m/s and h=6.626x10^-34 jxs) 1.63x10^-24 J. What is the …
WebApr 12, 2024 · However, we know that energy is the product of power and time. Hence, the energy generated in Joules can be equated to a watt second. 1 watt-second = 1 Joule. … recipe for no bean chiliWebMar 23, 2024 · Calculate the energy, in joules, of a photon of green light having a wavelength of 562nm? The answer is 3.54 ×10−19 J. The equation for determining the … unnecessary stressWebOct 28, 2015 · Best Answer. E=hv, where h is Planck's constant, v is the frequency. E= (6.63 X 10^-34) X (7.91 X 10^10) E=5.24433 X 10^-23, Joules-the energy of a single … unnecessary string interpolationWebThe total energy required will be this mass times the specific heat times the change in temperature and we'll assume that the specific heat of the soup is the same as that of water 4186 joules per kilogram per Celsius degree. … recipe for no cook ice box fruit cakeWebCalculate the amount of microwave energy in joules needed to raise the temperature of 1.00 kg of soup from 20.0ºC to 100ºC. What is the total momentum of all the microwave photons it takes to do this? Calculate the velocity of a 1.00- kg mass with the same momentum. What is the kinetic energy of this mass? Expert Answer 100% (5 ratings) recipe for no churn vanilla ice creamWebMar 27, 2024 · To calculate the energy of a photon, follow these easy steps: If you know the wavelength, calculate the frequency with the following formula: f =c/ λ where c is the speed of light, f the frequency and λ the wavelength. If you know the frequency, or if you just … Click on the unit changer menu of the momentum row and select x10-35 from … unnecessary spaces. learn more atWebSo the energy required from the microwave photons then is going to be 1.00 kilogram of mass times 4186 joules per kilogram per Celsius degree times 80.0 Celsius degrees— temperature change— which is 3.35 times … recipe for no cook banana pudding